[PDF]Contents - CCP Interactivehttps://ccpinteractive.com/cfiles/pdf_sample/CC3215S.pdfCachedby T GUIDE - âCited by 3 - âRelated articlesFor this ...
12 downloads
140 Views
3MB Size
Contents
.................. TEACHER GUIDE • NCTM Content Standards Assessment Rubric ........................................... • How is Our Resource Organized? ............................................................... • The NCTM Principles & Standards .............................................................
4 5 6
STUDENT HANDOUTS • Exercises Warm-Up Drill 1 ........................................................................................ Timed Drill 1 (5 minutes) ........................................................................ Timed Drill 2 (3 minutes) ........................................................................ Warm-Up Drill 2 ........................................................................................ Timed Drill 3 (4 minutes) ........................................................................ Timed Drill 4 (6 minutes) ........................................................................ Warm-Up Drill 3 ........................................................................................ Timed Drill 5 (4 minutes) ........................................................................ Timed Drill 6 (5 minutes) ........................................................................ Warm-Up Drill 4 ........................................................................................ Timed Drill 7 (5 minutes) ........................................................................ Timed Drill 8 (4 minutes) ........................................................................ Warm-Up Drill 5 ........................................................................................ Timed Drill 9 (6 minutes) ........................................................................ Warm-Up Drill 6 ........................................................................................ Timed Drill 10 (3 minutes) ...................................................................... Timed Drill 11 (5 minutes) ...................................................................... • Review ........................................................................................................ EZ
7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24
EASY MARKING™ ANSWER KEY ............................................................ 27 MINI POSTERS ......................................................................................... 30
FREE!
4 6 BONUS Activity Pages! Additional worksheets for your students
NAME:
• Go to our website: www.classroomcompletepress.com/bonus • Enter item CC3215 • Enter pass code CC3215D for Activity Pages.
Student Worksheet
...................
Activity Six NAME:
Student Worksheet
a) Look at the shapes below. The measurements of each shape are labeled. Use these ................... measurements to find the area of each shape. Then, use the measurements to find the perimeter of each shape as well. Note: measurements are not to scale.
Activity Five NAME:
iv) 84°F =
NAME:
NAME:
Student Worksheet
Student Worksheet
ii)
= Alligator
ii) 12500 ounces
=
=
=
=
=
=
ii) A student was able to toss a softball 50 yards (45.7 meters) during a field day v) 1290 grams competition. How many inches (cm) did the softball travel?
=
=
=
=
vii) = Coyote
=
=
viii) = Elephant (African)
iii) An equilateral triangle has a perimeter of 18 inches (45.7 cm). What is the length vi) 4500ofpounds each side? vii) 800 centigrams iv) The volume of a cube is 1.7 cubic inches (27 cubic cm). What is the length of each side? viii) 29,200 ounces v) Janice uses a 1 gallon (4 liter) jug to fill up an aquarium. She fills the jug six times, and ix) (liters) 2575 milligrams empties five and one-half jugs of water into the aquarium. How many quarts of water does the aquarium hold? x) 895 decagrams vi) A square has an area of 22 sq inches (144 sq cm). What is the perimeter of the xi) 950 grams square?
=
=
=
=
=
=
iii)
=
iv)
=
v)
=
vi)
ix)
Baboon Bear (black) Bison Cheetah
= Giraffe
x)
=
xi)
=
xii)
Hippopotamus Koala Bear Leopard
=
=
vii) A circle has a diameter of 2 inches (5 cm). What is its area?
=
=
xiv) = Mongoose
=
=
xv) = Monkey
ix) A regular hexagon has a perimeter of 11 sq in (72 sq cm). What is the lengthxiv) of each 74 kilograms side? xv) 2950 grams x) Albert measures the temperature on a cold winter day. It is 18°F (-8°C). What would the temperature be 15 degrees warmer? xvi) 5.5 tons
=
=
=
=
=
=
xii) 8200 pounds viii) The base of a triangle measures 7 inches (18 cm)? The area is 8.5 sq in (54 sq cm). xiii) 3400 milligrams What is the height of the triangle?
xi) The length of a tree shadow is 18 feet (5.5 meters). How many inches (cm) is the xvii) 19 kilograms shadow? xii) The area of a basketball court is 600 square feet (55.5 square meters). If the length is xviii) 245 grams 30 feet (9 meters), how wide is the court? xix) 18,295 milligrams xiii) Carlos left home at 7:30 am to walk to school. It took him one-quarter of an hour to arrive at a local market, where he bought milk for lunch. It took him one of ounces xx)third 36000 that time to get to school. How long, in total, did it take Carlos to walk to school? xiv) A car measures a length of 236 inches (600 cm). How many feet (meters) ©long is it?
= = = =
=
= =
Lion
xvi) = Rhinoceros Tiger (Bengal) = xviii) Turtle = xix) Wolverine = xx) Zebra xvii)
=
2A
=
xiii)
=
©
=
°C
iii) 47°F =
°C
Area = vi) -4°F =Perimeter =
°C
iv) ix) 270°F =
°C
person would find the area and perimeter. Then, find the actual area and perimeter x) -40°F = °C xi) 99°F = of the triangle and label it below.
moon has 1/6 the gravity of the Earth. For this reason, a man weighing 100 pounds (45.5 kilograms) on Earth weighs about 16.7 pounds (7.6 kilograms) on the moon. You have been placed in charge of opening a zoo at a space station on the moon. Based on the gravity found on the moon, what would the following animals weigh the zoo? a) Look at the measurements below. List three other standard orat metric equivalents that equal the same measurement. Animal Weight on Earth Weight on the Moon i) 180 pounds (81.7 kg) = = Aardvark i) 1500 milligrams =
...................
Activity One
ii) 25°F = v) 160°F =
vii) 320°F = °C viii) 188°F = ................... In a well articulated paragraph (including at least five sentences) explain how a
................... a) Objects on the moon weigh about 1/6 of their weight on the Earth because the
Activity Two
iii) 185 kilograms i) A rectangle has an area of 12 square inches (77.5 square cm). If the length is 3 inches (7.6 cm), what is the width? iv) 32 tons
a) Complete the following measurement word problems below.
iii) 1.5 in (4 cm)
°C
5 in (12.5 cm)
°C °C
Area = Perimeter =
v)
vi)
2 in (5 cm)
2.5 in (6 cm)
xii) 318°F =
°C
xiii) 72°F =
°C
xiv) -100°F =
°C
Area = xv) 450°FPerimeter = =
°C
Area = Perimeter =
xvi) 800°F =
°C
xvii) 325°F =
°C
xviii) 56°Fvii) =
°C
viii)
450 pounds (204.1 kg)
ix) 4 in (10 cm)
1.2 in (3 cm)
2.8 in (7 cm)
2.8 in (7 cm)
6 in (15 cm) 2 in (5 cm)
°F
ii) 80°C =
°F
= iii) 101°CArea = Perimeter =
°F
v) -5°C =
°F
vi) 200°C = x)
°F
8 in (20 cm)
6 in (15 cm)
Area = Perimeter =
2.5 in (6 cm)
2.2 in (5.5 cm)
i) 12°C = iv) 92°C = vii) 120°C =
3 in (7.5 cm)
0.8 in (2 cm)
b) Convert the following temperatures in Celsius to Fahrenheit.
90 pounds (40.8 kg)
1.2 in (3 cm)
2 in (5 cm)
Area = Perimeter =
1.3 in (3.5 cm)
500 pounds (226.8 kg)
iii)
3 in (7.5 cm)
°C °C
Student Worksheet a) Suppose you had to explain how to find the area and perimeter of the triangle below.
Activity Three
i)
Student Worksheet a) Convert the following temperatures in Fahrenheit to Celsius.
................... i) 18°F =
Activity Four NAME:
°F °F 6.5 in (16.5 cm)
viii) 45°C =
°F
ix) -18°C =
x) 47°C =
°F
xi) 290°C =
°F
xii) 32°C Area = =
xiii) 158°C =
°F
xiv) 492°C =
°F
xv) -27°C =
°F
xvi) 44°C =
°F
xvii) -9°C =
°F
© xviii) 188°C =
°F
°F
Area = Perimeter =
Area = Perimeter =
xi)
xii) 1.3 in (3.5 cm)
3.5 in (8.5 cm)
2200 pounds (997.9 kg) 140 pounds (63.5 kg)
°F
Perimeter =
20 pounds (9.1 kg) 8000 pounds (3628.7 kg) 1800 pounds (816.5 kg) 4500 pounds (2041.2 kg)
3 in (7.5 cm)
Area = Circumference =
6A
Area = Perimeter =
Measurement – Drill Sheets CC3215
18 pounds (8.2 kg) 100 pounds (45.4 kg) 400 pounds (181.4 kg)
5A
©
10 pounds (4.5 kg)
Measurement – Drill Sheets CC3215
21 pounds (9.5 kg) 4000 pounds (1814.4 kg) 600 pounds (272.2 kg) 300 pounds (136.1 kg)
©
4A
Measurement – Drill Sheets CC3215
25 pounds (11.3 kg) 800 pounds (362.9 kg) 3A
Measurement – Drill Sheets CC3215
=
Measurement – Drill Sheets CC3215
xv) A round trip between Millville and Boonesboro is 52,800 feet (16,093.4 meters). How many miles (km) is this trip one way? ©
3
1A
Measurement – Drill Sheets CC3215
Measurement – Drill Sheets CC3215
NAME:
i)
3 in (7.5 cm)
6 in (15 cm)
8 in (20 cm)
ii)
1.5 in (4 cm)
3.5 in (9 cm)
1.5 in (4 cm)
iii)
2 in (5 cm)
1.3 in (3 cm)
iv)
2 in (5 cm)
7 in (17.8 cm)
v)
2.8 in (7 cm)
5 in (12.5 cm)
vi)
2.5 in (6 cm)
1.5 in (4 cm)
vii)
2.2 in (5.5 cm)
1.5 in (4 cm)
viii)
3 in (7.5 cm)
7 in (17.8 cm)
8 in (20 cm)
3 in (7.5 cm)
ix)
1 in (2.5 cm)
2.5 in (6 cm)
1.3 in (3 cm)
3 in (7.5 cm)
x)
1.5 in (4 cm)
3.3 in (8.5 cm)
2.5 in (6 cm)
3.2 in (8 cm)
xi)
3 in (7.5 cm)
6 in (15 cm)
10 in (25.5 cm) 5 in (12.5 cm)
xii)
1.5 in (4 cm)
3.7 in (9.5 cm)
4.7 in (12 cm)
3.5 in (9 cm)
xiii)
3.5 in (9 cm)
1.8 in (4.5 cm)
3.2 in (8 cm)
2.5 in (6 cm)
xiv)
3 in (7.5 cm)
7.5 in (19 cm)
3 in (7.5 cm)
5 in (12.5 cm)
xv)
6 in (15 cm)
9 in (23 cm)
12 in (30.5 cm) 5 in (12.5 cm)
Perimeter if sizes are doubled
4 in (10 cm)
2.8 in (7 cm)
AC T
4.3 in (11 cm)
3.3 in (8.5 cm)
1.8 in (4.5 cm)
4.7 in (12 cm)
3.7 in (9.5 cm)
ii) Perimeter = 2.5 inches Shape 1
Shape 2
iii) Perimeter = 3 inches Shape 1
Shape 2
iv) Perimeter = 4 inches Shape 1
10
Shape 3
v) Perimeter = 5 inches Shape 1
Shape 2
Shape 3
vi) Perimeter = 4.5 inches Shape 1
Shape 2
Shape 3
Measurement – Drill Sheets CC3215
ES viii) 18 g =
p
xi) 29 c =
q
iii) 2.5 p = vi) 16 p =
c
iv) 9 q =
c
g
vii) 22 q =
g
ix) 32.5 p =
c
x) 15 q =
g
xii) 7.25 g =
q
xiii) 19.5 c =
p
ED
Tuesday
Wednesday
Thursday
Friday
Thursday
Friday
ii) What is the average high for the week?
iv) What is the mean temperature for each day? Monday
Tuesday
Wednesday
vi) What day has the smallest difference between high and low?
L
iii) 300 L =
L
v) 32.5 L =
mL vi) 2.5 kL =
kL
kL
ix) 5,216 L =
kL
x) 1300 mL =
L
kL
xii) 8.23 kL =
mL
xi) 50.26 L =
vii) What is the difference between the highest and lowest temperature during the week?
mL
mL viii) 2.6 L =
©
Monday
v) What day has the greatest difference between high and low?
ii) 50 mL =
L
Day: Difference:
Day: Mean:
vii) 0.5 L =
xiii) 0.075 kL =
Friday High: 72.7°F (22.6°C) Low: 54.8°F (12.7°C)
iii) What is the average low for the week?
kL
TIM
iv) 9.5 kL =
Thursday High: 78.4°F (25.8°C) Low: 60.3°F (15.7°C)
i) Calculate the difference between the high and low temperatures for each day.
b) Convert the following metric measurements.
i) 2 L =
Wednesday High: 77.9°F (25.5°C) Low: 52.5°F (11.4°C)
ED
q
q
Tuesday High: 77.2°F (25.1°C) Low: 56.8°F (13.8°C)
TIM
v) 12.5 g =
ITI
g
i) 12 c =
IV
ii) 60 q =
p
Monday High: 75.6°F (24.2°C) Low: 58.3°F (14.6°C)
The calendar below shows the daily high and low temperatures in Carver City for a five day period in July. Read the information, then answer the questions that follow.
ITI
14a)
ES
...................
Convert the following standard measurements.
40
Measurement – Drill Sheets CC3215
NAME:
Timed Drill Sheet # 9
AC T
Ex: 5 g =
21
©
................... 2a)
Shape 3
Shape 2
NAME:
Timed Drill Sheet # 1
Shape 3
IV
W AR
M
-U
P
2.5 in (6 cm)
Shape 3
P
12 in (30.5 cm) 8 in (20 cm)
©
Shape 2
2 in (5 cm)
Redo the activity above by finding the area of each triangle. Then, find the area of each triangle if the measurements of each side and height are doubled.
Reflection
i) Perimeter = 2 inches Shape 1
AC T
2.8 in (7 cm)
ITI
Perimeter
IV
Height
AC T
Side 3
-U
Side 2 (base)
Use a ruler to draw the following plane figure (or 2 dimensional) shapes for each perimeter given. For each perimeter, draw 3 different shapes that equal that measurement.
M
Side 1
15a)
Warm-Up Drill Sheet # 6
...................
W AR
Triangle
ITI
Look at the chart below. It shows the measurements of the sides of a triangle. Determine the perimeter of each triangle. Then, find the perimeter of each triangle if the measurements of each side are doubled.
IV
4a)
ES
...................
ES
NAME:
Warm-Up Drill Sheet # 2
FFind the high and low temperatures for the previous week for
Explore With Technology yyour own city and fill out the chart below accordingly. Day: High:
Monday
Tuesday
Wednesday
Thursday
Friday
Low:
xiv) 22,000 mL =
8
L
xv) 18.5 L =
Difference:
kL
Measurement – Drill Sheets CC3215
Mean:
©
20
Measurement – Drill Sheets CC3215
NAME:
NAME:
...................
T
Review B
T
Review A
...................
iii) 176 oz =
lbs
a) Convert the following measurements. i) 2.57 cm = mm ii) 4.5 ft =
in
iii) 12.5 gal =
cups
iv) 500 m =
km
v) 72 ft =
yd
vi) 7.5 kL =
L
iv) 5.5 km =
cm
v) 24 oz =
lbs
vi) 0.5 kL =
L
vii) 128 qts =
gallons
viii) 2.5 m =
cm
ix) 45 ft =
yd
vii) 138 in =
ft
viii) 175 mm =
cm
ix) 30 qt =
gallons
x) 7 km =
mm
xi) 4.5 cup =
pt
xii) 12 L =
mL
x) 19.27 mg =
g
xi) 28.5 oz =
lbs
xii) 29.25 kg =
g
xiii) 18.5 ft =
in
xiv) 29. 7 g =
mg
xv) 25 lbs =
oz
xiii) 22.5 ft =
in
xiv) 0.025 kL =
L
xv) 2.5 tons =
oz
ii) A rectangle had an area of 2.5 square inches (16 square cm). What are two possible combinations for the length and width of the rectangle?
M
SS
b) Answer the following quick measurement questions. i) Carlos measured the temperature on a cold winter day at -3°F. What was the temperature in Celsius?
SE
M
SS
SE
b) Answer the following quick measurement questions. i) Jaime measured the temperature of a warm liquid. The temperature started at 72°F (22°C) and dropped 2.5 degrees every minute for three minutes. What was the temperature of the liquid after 3 minutes?
EN
cm
EN
a) Convert the following measurements. i) 20 ft = in ii) 480 mm =
ii) A regular pentagon has a perimeter of 12 inches (30.5 cm). What is the measure of each side?
AS
AS
iii) Dionne weighed herself and determined she was 85.25 pounds (38.67 kilograms). How many ounces (grams) did she weigh?
iii) Tyrone ran a 5 mile (8 km) race. How many total feet (meters) did he run?
v) A triangle has a base of 6 inches (150 mm) and a height of 1 inch (25.5 mm). What is the area of the triangle?
v) A box has a length of 3 inches (8 cm), width of 2 inches (5 cm), and a height of 2.5 inches (7 cm). What is the volume of the box?
vi) What is the perimeter of a square with a side measuring 3.5 inches (9 cm)?
EW
iv) Wan took a car trip with his family. They traveled close to 158.5 miles (255 km) before arriving at their destination after three days. What was the average amount of miles (km) they traveled each day?
EW
iv) If a car weighs 2.5 tons, how many pounds (kilograms) does it weigh?
c) Use a ruler to measure the objects below. Find the perimeter or circumference for each object. i) ii) iii)
RE
RE
VI
VI
c) Use a ruler to measure the objects below. Find the area for each object. ii) iii) i)
Perimeter = Area =
Area =
Area = 24
©
Measurement – Drill Sheets CC3215
Perimeter =
Circumference =
25
©
Measurement – Drill Sheets CC3215
NAME:
...................
lbs
vii) 144 qt =
gal
viii) 1.25 km =
cm
x) 27.55 kg =
g
xi) 24.5 ft =
xiii) 25.25 g =
mg
xiv) 8.25 ft =
vi) 7.5 g =
kg
ix) 40.3 ft =
in
xii) 4.25 km =
m
in
xv) 0.028 kL =
L
SS
yds
S
v) 198 oz =
ER
mm
lbs
M
iv) 1.025 m =
iii) 0.25 tons =
ST
mm
EN
a) Convert the following measurements. i) 18.3 yd = ft ii) 1.28 cm =
T
Review C
SE
PO
b) Answer the following quick measurement questions. i) Steven measured the length of time it took for a science experiment to be completed. After three trials, his times were 18.25 seconds, 16.75 seconds, and 15.27 seconds. What was the average time for the experiments to be completed?
v) The radius of a circle is 5 inches (12.5 cm). What is the area of the circle?
RE
VI
c) Use a ruler to measure the objects below. Find the area, perimeter and circumference for each object. i) ii) iii)
Area =
Perimeter = ©
Area = Circumference = 26
Area = Perimeter = Measurement – Drill Sheets CC3215
IV
EW
iv) A rectangular box has a length of 3 inches (8 cm), a width of 2 inches (5 cm), and a height of 0.8 inches (2 cm). What is the surface area?
AC T
AS
iii) Diego rode a bike for three consecutive days. He averaged 25.25 miles (40.6 km) each day. How many total feet (meters) had he traveled after three days?
ITY
ii) A parallelogram has an area of 4.2 sq. in (27 sq. cm). What are two possible base and height measurements?
NAME:
Timed Drill Sheet # 6
................... 9a)
a)
a)
Formula Ex: P = 4 side
Shape it may Sample represent Shape Square
i) A = 1734 sq in (18.84 sq cm), C = 14.76 in (37.68 cm)
i) 4.81 (2.96), 0.08 (0.049) Perimeter ii) A = 7.065 sq in (44.16 sq cm),
Area
10.
11.
a)
a)
Answers may vary.
i) Triangle or Parallelogram
i) Perimeter = 5.2 in (12 cm), Area = 1.69 sq in (9 sq cm)
9.
C = 9.42 in (23.55 cm)
A=s
ii) 4.94 (3.04), 0.082cm) (0.051) P = 4 (0.8 in/2
2
4.99 (3.07), A = (0.8 in/2 cm)2 P = 3.2 in/8iii)cm 0.083 (0.051) iii) A = 4.52 sq in (28.26 sq cm), A = 0.64 sq.C in/ = 7.54 in (18.84 cm) iv) 5.05 (3.11), 4 sq.iv)cm A = 78.5 sq in (506.45 sq cm), C = 31.4 in (79.76 cm)
i) A = ½ b x h
v) A = 140.96 sq in (907.46 sq cm), C = 42.08 in (106.76 cm)
ii) P = 3s
vi) A = 9.62 sq in (63.59 sq cm), C = 10.99 in (28.26 cm) vii) A = 78.5 sq in (510.45 sq cm), C = 31.4 in (80.07 cm)
iii) A = l x w
viii) A = 2.54 sq in (15.9 sq cm), C = 5.65 in (14.13 cm)
ix) A = 167.33 sq in (1074.67 sq cm), C = 45.84 in (116.18 cm)
iv) P = 5s
x) A = 1766.25 sq in (1133.54 sq cm), C = 47.1 in (119.32 cm)
ii) Triangle
iii) Quadrilateral
0.084 (0.052)
v) 5.11 (3.15), 0.085 (0.053) vi) 5.12 (3.15), 0.085 (0.053) vii) 5.12 (3.15), 0.085 (0.053) viii) 5.13 (3.16), 0.086 (0.053) ix) 5.19 (3.19), 0.087 (0.053)
iv) Pentagon
v) Circle
vi) Quadrilateral
ii) Perimeter = 4.2 in (10 cm), Area = 1.04 sq in (6 sq cm) iii) Perimeter = 4 in (10 cm), Area = 1 sq in (6.25 sq cm) iv) Perimeter = 5.2 in (12 cm), Area = 4.4 sq in (10.6 sq cm) v) Perimeter = 3 in (7.4 cm), Area = 0.28 sq in (1.7 sq cm)
17
12. a)
13.
EZ
©
Listed below in the first column are the formulas that are used to determine the area, surface area, or perimeter of different shapes. Write the shape that each formula represents in the second column. Then, using a ruler, draw a sample of each shape7.using inches or 8. centimeters. Determine the area or perimeter for each shape you draw.
a) i) 22 sq in (137.5 sq cm) ii) 184 sq in (1150 sq cm) iii) 192 sq in (1200 sq cm)
i) 12 ft = 144 in
iv) 117 sq in (765 sq cm)
ii) 0.5 yd = 1.5 ft
v) 324 sq in (2025 sq cm)
iii) 72 in = 2 yds iv) 7.5 ft = 2.5 yds
vi) 9.5 sq in (58 sq cm)
v) 2.5 yds = 90 in
vii) 1398 sq in (8969 sq cm)
vi) 21 ft = 252 in
viii) 27 sq in (175 sq cm)
vii) 78 in = 6.5 ft viii) 30 yds = 1080 in
ix) 802 sq in (5118 sq cm)
ix) 3.3 yd = 118.8 in
x) 300 sq in (1924 sq cm)
x) 42 in = 3.5 ft
xi) 216 sq in (1350 sq cm)
xi) 16 in = 1.3 ft
EASY MARKING ANSWER KEY v) A = π r2
vi) P = 21 + 2w
xi) A = 248.72 sq in (1589.63 sq cm), C = 55.89 in (141.3 cm)
x) 5.25 (3.23), 0.088 (0.054)
xii) A = 0.79 sq in (4.91 sq cm), C = 3.14 in (7.85 cm)
xi) 5.28 (3.25), 0.088 (0.054)
xiii) A = 15.9 sq in (103.82 sq cm), C = 14.13 in (36.11 cm)
xiv) A = 415.27 sq in (2686.47 sq cm), C = 72.22 in (183.69 cm) Measurement – Drill Sheets CC3215
vii) A = s2
viii) P = 6s
ix) A = 6a2
©
15
xv) A = 113.04 sq in (735.05 sq cm), C = 37.68 in (96.1 cm) xvi) A = 12.56 sq in (78.5 sq cm), C = 12.56 in (31.4 cm) xvii) A = 153.86 sq in (994.88 sq cm), C = 43.96 in (111.78 cm)
13
xii) 5.58 (3.43), 0.093 (0.057)
xiii) 5.59 (3.44), 0.093 (0.057) xiv) 5.62 (3.46), 0.094 (0.058)
vii) Square
viii) Hexagon
vi) Perimeter = 5.2 in (13 cm), Area = 1.6 sq in (10 sq cm)
Measurement – Drill Sheets CC3215
xiii) 3 m = 3,000 mm
xiv) 2.5 cm = 250 mm
xii) 192 sq in (1200 sq cm)
xiii) 304 sq in (1900 sq cm) xiv) 52 sq in (325 sq cm)
xv) 19 cm = 190 mm
ix) Cube
vii) Answers will vary.
xvi) 14 m = 1400 cm
viii) Answers will vary.
xvii) 855 mm = 0.855 m
Shapes will vary. Areas and Perimeters will vary.
xviii) 9.5 cm = 0.095 m
xx) 29 cm = 290 mm xxi) 25 cm = 0.25 m xxii) 1890 mm = 189 cm 15
xv) 365 sq in (2334 sq cm) xvi) 51.5 sq in (328 sq cm) xvii) 5.5 sq in (33 sq cm)
xix) 326 mm = 32.6 cm
xv) 5.75 (3.54), 0.096 (0.059) 14
xii) 26.5 yds = 79.5 ft
16
18
xviii) 351 sq in (2250 sq cm) xix) 184.5 sq in (1148 sq cm) xx) 220 sq in (1387.5 sq cm) 19